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From linux-crypto-bounce@nl.linux.org Fri May 05 15:03:18 2006
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Message-ID: <445B4CD7.1030909@gmail.com>
Date: Fri, 05 May 2006 16:02:15 +0300
From: Alon Bar-Lev <alon.barlev@gmail.com>
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Hello Jari,

I am a heavy happy user of your loop-aes component. So first
of all I want to thank you for your work.

I've implemented some wrapping to enable users to use Linux,
suspend2, loop-aes and PKCS#11 in order to have a secure
mobile environment
(http://wiki.suspend2.net/EncryptedSwapAndRoot).

I've just went through some of the eCryptfs code and I've
noticed they are using the kernel access key retention to
move keys from user space into kernel. It looks quite clean
implementation so that it does not require any patch to
util-linux.

I know that you support kernel 2.0 and above, so the
util-linux patch is required... But maybe for newer kernels
you can allow the kernel key interface support.

I thought of something like user mode for /dev/loop0 and
multi-key-v3:
{
	echo AES256
	gpg < keyfile.gpg
} | keyctl padd user loop:0 @u

Then use losetup or mount without any patches.

The loop:# is required in order to allow a simple
/etc/request-key.conf configuration for loop keys. So even
if key is not provided the /sbin/request-key can instantiate it.

Just an idea...

Best Regards,
Alon Bar-Lev.


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From linux-crypto-bounce@nl.linux.org Sun May 07 02:38:22 2006
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Hi!

Since Loop-AES features a patch for amd64 cpus when using AES cipher it runs
faster creating less load. So everyone will use AES. Twofish and Blowfish
ciphers are considerably slower. But, is there a patch for Twohfish /
Blowfish to make them work faster on amd64??
I´d like to use both ciphers for the same partition, unfortunately both are
much slower than AES. Will this be the same forever?

Best regards,
Peter

-- 
Echte DSL-Flatrate dauerhaft für 0,- Euro*!
"Feel free" mit GMX DSL! http://www.gmx.net/de/go/dsl

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From linux-crypto-bounce@nl.linux.org Sun May 07 17:59:38 2006
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From: Jari Ruusu <jariruusu@users.sourceforge.net>
To: Peter_22@gmx.de
Cc: linux-crypto@nl.linux.org
Subject: Re: Loop-AES and Twofish on 64-bit CPU
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Peter_22@gmx.de wrote:
> Since Loop-AES features a patch for amd64 cpus when using AES cipher it=
 runs
> faster creating less load. So everyone will use AES. Twofish and Blowfi=
sh
> ciphers are considerably slower. But, is there a patch for Twohfish /
> Blowfish to make them work faster on amd64??
> I=B4d like to use both ciphers for the same partition, unfortunately bo=
th are
> much slower than AES. Will this be the same forever?

Joachim Fritschi posted partially assembler implementation of twofish for
AMD64 to linux-kernel mailing list today. I haven't looked at it yet.

For blowfish... my advise is to not use blowfish to encrypt large amounts=
 of
data. It has 64 bit block size, and it is present in loop-AES' additional
ciphers package mostly for compatibility with some old implementations.

--=20
Jari Ruusu  1024R/3A220F51 5B 4B F9 BB D3 3F 52 E9  DB 1D EB E3 24 0E A9 =
DD

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Date: Sun, 07 May 2006 18:39:44 +0300
From: Jari Ruusu <jariruusu@users.sourceforge.net>
To: Alon Bar-Lev <alon.barlev@gmail.com>
Cc: linux-crypto@nl.linux.org
Subject: Re: Loop-AES and kernel access key retention
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Alon Bar-Lev wrote:
> I've just went through some of the eCryptfs code and I've
> noticed they are using the kernel access key retention to
> move keys from user space into kernel. It looks quite clean
> implementation so that it does not require any patch to
> util-linux.

(1) Keyctl userland-to-kernel interface is based on strings, and encrypted
    loops want hashed binary data. Not compatible without extra tricks.

(2) Userspace utilities make no attempt to overwrite secret key material
    after they are done with it. Serious newbie goofs.

(3) Significant amounts of loop would need to be rewritten because ioctl()
    and request_key() interfaces are so different, yet the benefits would be
    almost zero.

(4) Mainline linux motto is: "there is no stable API" which usually
    translates to "don't bother writing code to this API". I have seen too
    may interfaces change/break under my feet that I am reluctant to add
    another dependency to another possibly wildly changing API.

-- 
Jari Ruusu  1024R/3A220F51 5B 4B F9 BB D3 3F 52 E9  DB 1D EB E3 24 0E A9 DD

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Date: Sun, 07 May 2006 19:02:16 +0300
From: Alon Bar-Lev <alon.barlev@gmail.com>
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To: Jari Ruusu <jariruusu@users.sourceforge.net>
CC:  linux-crypto@nl.linux.org
Subject: Re: Loop-AES and kernel access key retention
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Jari Ruusu wrote:
> Alon Bar-Lev wrote:
>> I've just went through some of the eCryptfs code and I've
>> noticed they are using the kernel access key retention to
>> move keys from user space into kernel. It looks quite clean
>> implementation so that it does not require any patch to
>> util-linux.

Thank you for your reply!

> (1) Keyctl userland-to-kernel interface is based on strings, and encrypted
>     loops want hashed binary data. Not compatible without extra tricks.

I am under the impression that it can hold binary data. You
can pipe data to it. I've tried it and it works.

> (2) Userspace utilities make no attempt to overwrite secret key material
>     after they are done with it. Serious newbie goofs.

Well... If this was the only problem, I would have worked
with the author to fix it to your satisfaction :)

> (3) Significant amounts of loop would need to be rewritten because ioctl()
>     and request_key() interfaces are so different, yet the benefits would be
>     almost zero.

I am under the impression that it should be quite easy. I've
looked at the eCryptfs code:

---

#include <linux/key.h>
<snip>
#define KEY_PAYLOAD_DATA(key) \
        (((struct user_key_payload*)key->payload.data)->data)
#define KEY_PAYLOAD_LEN(key) \
        (((struct user_key_payload*)key->payload.data)->datalen)
<snip>
        auth_tok_key = request_key(&key_type_user,

mount_crypt_stat->global_auth_tok_sig,
                                   NULL);
        if (!auth_tok_key || IS_ERR(auth_tok_key)) {
                ecryptfs_printk(KERN_ERR, "Could not find
key with "
                                "description: [%s]\n",

mount_crypt_stat->global_auth_tok_sig);
                process_request_key_err(PTR_ERR(auth_tok_key));
                rc = -EINVAL;
                goto out;
        }
        auth_tok = (struct ecryptfs_auth_tok
*)KEY_PAYLOAD_DATA(auth_tok_key);

---

> (4) Mainline linux motto is: "there is no stable API" which usually
>     translates to "don't bother writing code to this API". I have seen too
>     may interfaces change/break under my feet that I am reluctant to add
>     another dependency to another possibly wildly changing API.

OK. It was just an idea... I thought it is simple enough to
support it. But I understand your position.

Best Regards,
Alon Bar-Lev.


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From: Jari Ruusu <jariruusu@users.sourceforge.net>
To: Alon Bar-Lev <alon.barlev@gmail.com>
Cc: linux-crypto@nl.linux.org
Subject: Re: Loop-AES and kernel access key retention
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Alon Bar-Lev wrote:
> Jari Ruusu wrote:
> > (1) Keyctl userland-to-kernel interface is based on strings, and encrypted
> >     loops want hashed binary data. Not compatible without extra tricks.
> 
> I am under the impression that it can hold binary data. You
> can pipe data to it. I've tried it and it works.

Keyctl does strlen() on the key string. Null bytes won't work.

> > (2) Userspace utilities make no attempt to overwrite secret key material
> >     after they are done with it. Serious newbie goofs.
> 
> Well... If this was the only problem, I would have worked
> with the author to fix it to your satisfaction :)

It would need a user space program to be written anyway. The keys need to be
hashed, in userspace. Doing that in kernel would be insane.

> > (3) Significant amounts of loop would need to be rewritten because ioctl()
> >     and request_key() interfaces are so different, yet the benefits would be
> >     almost zero.
> 
> I am under the impression that it should be quite easy. I've
> looked at the eCryptfs code:

I quickly read the code and it looked like that request_key() may sleep.
Code paths were this request_key() would be inserted, may not sleep for any
significant amount of time. It holds locks. Locking re-write -> not funny.

There are many missing bits: For example, where do offset= and sizelimit=
options come from if they are not in /etc/fstab and parsed by mount and
losetup.

-- 
Jari Ruusu  1024R/3A220F51 5B 4B F9 BB D3 3F 52 E9  DB 1D EB E3 24 0E A9 DD

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From: Peter_22@gmx.de
To: Jari Ruusu <jariruusu@users.sourceforge.net>
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Subject: Re: Loop-AES and Twofish on 64-bit CPU
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> --- Ursprüngliche Nachricht ---
> Von: Jari Ruusu <jariruusu@users.sourceforge.net>
> An: Peter_22@gmx.de
> Kopie: linux-crypto@nl.linux.org
[...]
> Betreff: Re: Loop-AES and Twofish on 64-bit CPU
> Joachim Fritschi posted partially assembler implementation of twofish for
> AMD64 to linux-kernel mailing list today. I haven't looked at it yet.
 
Can this code be integrated in the next Loop-AES cipher package? I´d also
volunteer for a pre-test.

> For blowfish... my advise is to not use blowfish to encrypt large amounts
> of
> data. It has 64 bit block size, and it is present in loop-AES' additional
> ciphers package mostly for compatibility with some old implementations.

Blow- and Twofish are the only alternatives to AES. I´d like to use two
loops on one partition and use at least two ciphers to gain better security.
Size of devices in my case is 200GB (my complete old WD drive) and large
portions of the newer 320GB drive. With perpendicular recording drive space
will increase considerably in the next months. Do you see a limit where AES
or other ciphers can no longer cope with that?
With a passthru kernel patch
(http://www.kernel.org/pub/linux/kernel/people/jgarzik/libata/old/) I
managed to turn on and off my old 200GB serial ata drive. The command is
"hdparm -y /dev/sdb". This way you easily get more encrypted storage without
mounting dozens of dvd images and all that crap.
Anyway, 64bit implementations of any cipher are always welcome.

Regards,
Peter

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* Peter_22@gmx.de wrote:

> Blow- and Twofish are the only alternatives to AES. I?d like to use
> two loops on one partition and use at least two ciphers to gain
> better security.

There's also serpent.

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> --- Ursprüngliche Nachricht ---
> Von: markus reichelt <ml@mareichelt.de>
> An: linux-crypto@nl.linux.org
> Betreff: Re: Loop-AES and Twofish on 64-bit CPU
> Datum: Sun, 07 May 2006 23:32:57 +0200
> 
> * Peter_22@gmx.de wrote:
> 
> > Blow- and Twofish are the only alternatives to AES. I?d like to use
> > two loops on one partition and use at least two ciphers to gain
> > better security.
> 
> There's also serpent.

Which is, to my knowledge, derived from AES. I´d wonder if serpent is
optimized for amd64 cpu. So far I can assure to everyone that the 64bit
optimization for AES was a breakthrough.

Regards,
Peter

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* Peter_22@gmx.de wrote:

> > > Blow- and Twofish are the only alternatives to AES. I?d like to use
> > > two loops on one partition and use at least two ciphers to gain
> > > better security.
> >=20
> > There's also serpent.
>=20
> Which is, to my knowledge, derived from AES.

They are similar, but serpent is more secure.=20

http://www.cl.cam.ac.uk/~rja14/serpent.html


> I?d wonder if serpent is optimized for amd64 cpu.

Not natively; but maybe there's some fancy code snippet out there, I
don't know.

This year both Intel's and AMD's production of 32bit CPUs will run
out. They focus on the shiny 64bit production lines, so that means
better chances for code optimization. Eventually. ;-)

--=20
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* Peter_22@gmx.de wrote:

> Blow- and Twofish are the only alternatives to AES. I?d like to use
> two loops on one partition and use at least two ciphers to gain
> better security.

Regarding better security, I've just found out about an interesting
event: Quo Vadis 4 Conference, Friday 26 May 2006, Warsaw, Poland

It's interesting because of this:

http://www.cryptosystem.net/aes/

"Nicolas T. Courtois has announced that he will make a public
demonstration of an algebraic attack that breaks a toy block cipher
with about 200 S-boxes (nearly as many as in AES), by solving a
system of algebraic equations derived from very few (only 4)
plaintexts, ciphertext pairs. The cipher has good diffusion, no
special structure that could make it weak, and no known weakness (and
probably no weakness whatsoever) other than the low I/O degree of its
S-boxes."

--=20
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Peter_22@gmx.de wrote:

>>--- Ursprüngliche Nachricht ---
>>Von: markus reichelt <ml@mareichelt.de>
>>An: linux-crypto@nl.linux.org
>>Betreff: Re: Loop-AES and Twofish on 64-bit CPU
>>Datum: Sun, 07 May 2006 23:32:57 +0200
>>
>>* Peter_22@gmx.de wrote:
>>
>>    
>>
>>>Blow- and Twofish are the only alternatives to AES. I?d like to use
>>>two loops on one partition and use at least two ciphers to gain
>>>better security.
>>>      
>>>

First I would like to mention that this is not likely to increase the 
security in any way. The ciphers
are well analyzed and have no known attacks. If there are weak spots in 
the scheme it is likely
to be in the loop-implementation itself, since this is far less 
analyzed, and in that case an extra
layer of encryption is more likely to weaken security than to strengthen 
it. (Note: I don't know of
any exploitable holes in the loop implementation, I just say that more 
people have tried to find holes
in AES)

>>There's also serpent.
>>    
>>
>
>Which is, to my knowledge, derived from AES. 
>
Serpent is not derived from AES. It was one of the five final canditates 
to be AES, which the
algorithm Rijndael (now known as just AES) won. So it was a competing 
candidate for being
AES, and based on a quite different design. The other final candidates 
were Twofish and RC6 and Mars.
Serpent is considered by many cryptographers to be a good number two, 
others like Twofish. Nobody
like Mars, and RC6 is patented. All of them are belived to be secure.

>I´d wonder if serpent is
>optimized for amd64 cpu. So far I can assure to everyone that the 64bit
>optimization for AES was a breakthrough.
>
>  
>
Unlike AES, Serpent don't have immidiate gain from a 64-bit CPU, as it 
is quite close to
optimal on a 32-bit chip, and it don't need the extra registers on the 
AMD64 architecture to be fast.
In fact it does only read the keys and the input during an encryption. 
Just look at the emited assembly
code of the serpent function (-O2 -fomit-frame-pointer), and it is quite 
well optimized.

One difference however, is that the AMD chips has more ALUs, and can 
thus do more arithmetric
operation in parallel, which means that different sets of sbox-functions 
will be optimal on the two
CPUs, but the one being optimal on opteron will be  almost optimal on 
PIII and PIV, so this set
of sboxes is already in the current implementation of serpent.

Another thing is that since serpent don't gain so much from a new 
instruction set, the differences between
the 64-bit CPUs from AMD and intel may be as important as the difference 
between the 64 and 32-bit
chips.

What you can gain from a 64-bit CPU is that serpent then can run two 
encryptions in parallell
(but not in CBC-mode unfortunatly) or two decryptions in parallell (also 
in CBC-mode), and this will
double the speed of serpent. Unfortunatly this does not fit with the 
kernel API for crypto, so it is not
implemented. Brian Gladman developed such an implementation once using 
the MMX instuction set,
as this was before the AMD64 existed.

Dag Arne Osvik's paper on optimization of Serpent: 
http://www.osvik.no/pub/aes3.pdf

This paper describe a search function for sboxes for serpent. The sboxes 
in the current implementation
was found with a bit different method, but you get an impression.

-Gisle

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=0D
From:Derrick Martins=0D
Manchester G37 7FT,=0D
United Kingdom.=0D
Tel:44 704-013-1898=0D
Fax:44-870-135-4914=0D
E-mail:derrickmartins@myway.com=0D
=0D
=0D
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eputable clients that =0D
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are honest and trustworthy. We work in collaboration with top firms all o=
ver the world =0D
as we have earned a name as a service whose hallmarks in reliability and =
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rvices to satisfaction. =0D
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d are clean, clear and=0D
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ll as providing the =0D
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ion..=0D
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4) Your Fax Number: __________________________=0D
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6) The Name of the Closest Airport to your City of Residence:____________=
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I await your response Urgently.=0D
=0D
Derrick Martins=0D




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From: Gregor Zattler <telegraph@gmx.net>
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Hi,

"Government to force handover of encryption keys"
http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c

does loop-aes provide some kind of deniability?  

Does any other free crypto system?

Ciao, Gregor
-- 
 -... --- .-. . -.. ..--.. ...-.-

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Linux-crypto:  cryptography in and on the Linux system
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Date: Fri, 19 May 2006 13:35:33 +0200
From: "Antonio Di Salvo" <disalvo.antonio@gmail.com>
To: linux-crypto <linux-crypto@nl.linux.org>
Subject: Re: How about deniability? (read: http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
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truecrypt offers a feature called hidden volume that makes use of a
nested encrypted file system. If forced, you can reveal the password
of the outer volume, while the one that really holds sensitive data is
hidden and cannot be distinguished from random data.
they give an explanation at this url: http://www.truecrypt.org/hiddenvolume=
.php

I'm not aware if loop-aes provides something similar, so I cannot
answer you. However, I think not (IMHO). If someone know if it is
possibile to have completely random-looking data on the disk with root
partition encryption, please let me know.

Byez!

PS: sorry for the english!

On 5/19/06, Gregor Zattler <telegraph@gmx.net> wrote:
> Hi,
>
> "Government to force handover of encryption keys"
> http://www.zdnet.co.uk/print/?TYPE=3Dstory&AT=3D39269746-39020330t-100000=
25c
>
> does loop-aes provide some kind of deniability?
>
> Does any other free crypto system?
>
> Ciao, Gregor
> --
>  -... --- .-. . -.. ..--.. ...-.-
>
> -
> Linux-crypto:  cryptography in and on the Linux system
> Archive:       http://mail.nl.linux.org/linux-crypto/
>
>

-
Linux-crypto:  cryptography in and on the Linux system
Archive:       http://mail.nl.linux.org/linux-crypto/



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I have all my disks completly encrypted. The boot partition is on a
usb-stick. There is a section on this in the loop-aes.readme.

Antonio Di Salvo wrote:
> truecrypt offers a feature called hidden volume that makes use of a
> nested encrypted file system. If forced, you can reveal the password
> of the outer volume, while the one that really holds sensitive data is
> hidden and cannot be distinguished from random data.
> they give an explanation at this url:
> http://www.truecrypt.org/hiddenvolume.php
> 
> I'm not aware if loop-aes provides something similar, so I cannot
> answer you. However, I think not (IMHO). If someone know if it is
> possibile to have completely random-looking data on the disk with root
> partition encryption, please let me know.
> 
> Byez!
> 
> PS: sorry for the english!
> 
> On 5/19/06, Gregor Zattler <telegraph@gmx.net> wrote:
> 
>> Hi,
>>
>> "Government to force handover of encryption keys"
>> http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c
>>
>> does loop-aes provide some kind of deniability?
>>
>> Does any other free crypto system?
>>
>> Ciao, Gregor
>> -- 
>>  -... --- .-. . -.. ..--.. ...-.-
>>
>> -
>> Linux-crypto:  cryptography in and on the Linux system
>> Archive:       http://mail.nl.linux.org/linux-crypto/
>>
>>
> 
> -
> Linux-crypto:  cryptography in and on the Linux system
> Archive:       http://mail.nl.linux.org/linux-crypto/
> 
> 

-
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Archive:       http://mail.nl.linux.org/linux-crypto/



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-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

Gregor Zattler wrote:
> Hi,
> 
> "Government to force handover of encryption keys"
> http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c
> 
> does loop-aes provide some kind of deniability?  

No, at the moment not.

There are also a bunch of problems on such a feature if it is used on
loop devices and you don't dictate the filesystem.


> Does any other free crypto system?

Truecrypt (as mentioned)
Rubberhose
PhoneBook  (FUSE implementation)
StegFS (no development at the moment)
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Message-ID: <446E1C10.C33745EC@users.sourceforge.net>
Date: Fri, 19 May 2006 22:27:12 +0300
From: Jari Ruusu <jariruusu@users.sourceforge.net>
To: Gregor Zattler <telegraph@gmx.net>
Cc: linux-crypto <linux-crypto@nl.linux.org>
Subject: Re: How about deniability? (read: 
 http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
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Gregor Zattler wrote:
> does loop-aes provide some kind of deniability?

Yes, if you set it up that way. For example, if you set up a computer to
first try to boot from USB-stick, and then to try hard disk boot.

disk partition  Normal boot usage             Forced key handover boot usage
~~~~~~~~~~~~~~  ~~~~~~~~~~~~~~~~~             ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
/dev/hda1       not used                      unencrypted /boot
/dev/hda2       not used                      encrypted root
/dev/hda3       encrypted swap, random keys   encrypted swap, random keys
/dev/hda4       encrypted root                encrypted /tmp, random keys

USB-stick       Normal boot usage             Forced key handover boot usage
~~~~~~~~~       ~~~~~~~~~~~~~~~~~             ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
/dev/sda        unencrypted /boot             not used

You install some small distro on /dev/hda2, and never put any secret data
there. You install your normal distro on /dev/hda4, and put your secret data
there.

On normal usage, you always boot your computer from USB-stick to encrypted
root on /dev/hda4. Key files used for encrypting /dev/hda4 and /dev/hda2 are
different, and use different gpg passphrases. If you accidentally try to
boot from hard disk, you never enter the 'key handover' passphrase. When you
are forced to reveal the 'key handover' passphrase, your computer boots to
encrypted root on /dev/hda2. You can do that only *once*, because according
to /etc/fstab on /dev/hda2 root partition, mount sets up random loop
encryption keys on /dev/hda4, and runs 'mkfs' on /dev/hda4, effectively
overwriting file system structure there. After one such 'key handover' boot,
even when used with correct key file and passphrase from your USB-stick, you
or anyone else, have significant difficulties recovering data from
/dev/hda4.

-- 
Jari Ruusu  1024R/3A220F51 5B 4B F9 BB D3 3F 52 E9  DB 1D EB E3 24 0E A9 DD

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Subject: Re: How about deniability? (read:
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Jari Ruusu wrote:
> Gregor Zattler wrote:
>   
>> does loop-aes provide some kind of deniability?
>>     
>
> Yes, if you set it up that way. For example, if you set up a computer to
> first try to boot from USB-stick, and then to try hard disk boot.
>
> disk partition  Normal boot usage             Forced key handover boot usage
> ~~~~~~~~~~~~~~  ~~~~~~~~~~~~~~~~~             ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> /dev/hda1       not used                      unencrypted /boot
> /dev/hda2       not used                      encrypted root
> /dev/hda3       encrypted swap, random keys   encrypted swap, random keys
> /dev/hda4       encrypted root                encrypted /tmp, random keys
>
> USB-stick       Normal boot usage             Forced key handover boot usage
> ~~~~~~~~~       ~~~~~~~~~~~~~~~~~             ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> /dev/sda        unencrypted /boot             not used
>
> You install some small distro on /dev/hda2, and never put any secret data
> there. You install your normal distro on /dev/hda4, and put your secret data
> there.
>
> On normal usage, you always boot your computer from USB-stick to encrypted
> root on /dev/hda4. Key files used for encrypting /dev/hda4 and /dev/hda2 are
> different, and use different gpg passphrases. If you accidentally try to
> boot from hard disk, you never enter the 'key handover' passphrase. When you
> are forced to reveal the 'key handover' passphrase, your computer boots to
> encrypted root on /dev/hda2. You can do that only *once*, because according
> to /etc/fstab on /dev/hda2 root partition, mount sets up random loop
> encryption keys on /dev/hda4, and runs 'mkfs' on /dev/hda4, effectively
> overwriting file system structure there. After one such 'key handover' boot,
> even when used with correct key file and passphrase from your USB-stick, you
> or anyone else, have significant difficulties recovering data from
> /dev/hda4.
>
>   
Although I will agree that this provides a great deal of security for 
the data I don't think
that it provides 'deniability'. In particular if the attack consists of 
physical possession of the
computer and an analysis of the disk drive content without the attempt 
to boot it, and even
more so if the usb key is available to the attacker.

Truecrypt does provide some degree of deniability, although you have 
clearly demonstrated
previously its vulnerability to watermark attacks (which somewhat 
diminishes the deniability).



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From: Jari Ruusu <jariruusu@users.sourceforge.net>
To: Info <info@acculin.com>
Cc: linux-crypto@nl.linux.org
Subject: Re: How about deniability? 
 (read:http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
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Info wrote:
> Although I will agree that this provides a great deal of security for the
> data I don't think that it provides 'deniability'. In particular if the
> attack consists of physical possession of the computer and an analysis of
> the disk drive content without the attempt to boot it,

After handing over the passphrase to /dev/hda2 root partition, all hard disk
space is accounted for. Files on /dev/hda1 and /dev/hda2 are readable, and
user can prove that programs on /dev/hda2 root partition create random
encryption keys for /dev/hda3 and /dev/hda4 on each boot, and that user has
no way of knowing what earlier encryption keys were on those two partitions.

> and even more so if the usb key is available to the attacker.

Here user insists that /dev/hda2 is the root partition. That way all hard
disk space is accounted for. Attacker can prove existence of one small gpg
encrypted file on USB-stick for which user has forgotten passphrase.

-- 
Jari Ruusu  1024R/3A220F51 5B 4B F9 BB D3 3F 52 E9  DB 1D EB E3 24 0E A9 DD

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Cc: Info <info@acculin.com>, linux-crypto@nl.linux.org
Subject: Re: How about deniability?  (read:http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
References: <20060519104921.GA6018@pit.ID-43118.user.dfncis.de>		 <446E1C10.C33745EC@users.sourceforge.net> <446EA002.2090600@acculin.com> <446F157F.DFC04AA2@users.sourceforge.net>
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Jari Ruusu wrote:
> Info wrote:
> 
>>Although I will agree that this provides a great deal of security for the
>>data I don't think that it provides 'deniability'. In particular if the
>>attack consists of physical possession of the computer and an analysis of
>>the disk drive content without the attempt to boot it,
> 
> 
> After handing over the passphrase to /dev/hda2 root partition, all hard disk
> space is accounted for. Files on /dev/hda1 and /dev/hda2 are readable, and
> user can prove that programs on /dev/hda2 root partition create random
> encryption keys for /dev/hda3 and /dev/hda4 on each boot, and that user has
> no way of knowing what earlier encryption keys were on those two partitions.
> 
> 
>>and even more so if the usb key is available to the attacker.
> 
> 
> Here user insists that /dev/hda2 is the root partition. That way all hard
> disk space is accounted for. Attacker can prove existence of one small gpg
> encrypted file on USB-stick for which user has forgotten passphrase.

That just doesn't fly with for e.g. when you computer is sized by the 
police when you are away from home.

In a german magazine there was an article about disc duplication that 
was written by someone from the police.

They NEVER would boot a computer, as it is, after they sized it.
They take out the HDD and make a backup of it and only operate on these 
backups, then the computer and the original HDD(s) is locked away.
(The article was about the time and storage space it takes to make these 
kind of duplications of hard discs)

If you encrypted you computer right(tm) they woun't be able to break it, 
but the "self destruct" won't work either.




Bis denn

-- 
Real Programmers consider "what you see is what you get" to be just as
bad a concept in Text Editors as it is in women. No, the Real Programmer
wants a "you asked for it, you got it" text editor -- complicated,
cryptic, powerful, unforgiving, dangerous.


-
Linux-crypto:  cryptography in and on the Linux system
Archive:       http://mail.nl.linux.org/linux-crypto/



From linux-crypto-bounce@nl.linux.org Sat May 20 18:51:51 2006
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Date: Sat, 20 May 2006 19:49:47 +0300
From: "Michael Garibaldi" <michaelgari@gmail.com>
To: linux-crypto@nl.linux.org
Subject: Re: How about deniability? (read:http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
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>> Here user insists that /dev/hda2 is the root partition. That way all har=
d

>> disk space is accounted for. Attacker can prove existence of one small
gpg
>> encrypted file on USB-stick for which user has forgotten passphrase.
> That just doesn't fly with for e.g. when you computer is sized by the
police when you are away from home.

Obviously the police are not going to find one's USB stick on the computer,
when one is not home. The stick is ONLY used for booting and then carefully
hidden. It does not matter if the "self destruct" works or not, what matter=
s
is that there is absolutely no reason to even suspect that a different kind
of encryption is being used on the system. It boots from the HDD and uses
all the available space, and the police will get the key that will unlock
the fake system, and that's it. As long as the USB stick is kept safe (whic=
h
should be trivial to do), they have absolutely nothing to even suggest ther=
e
being a parallel system encrypted with other keys. And as Jari pointed out,
even if they actually get the USB stick too, they really cannot prove
anything.

P.S. they may, however, be smart enough to type one's name on Google and
find out that one has been discussing this topic on this public mailing
list.

------=_Part_14523_9474555.1148143787292
Content-Type: text/html; charset=ISO-8859-1
Content-Transfer-Encoding: quoted-printable
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&gt;&gt; Here user insists that /dev/hda2 is the root partition. That way a=
ll hard
<br>&gt;&gt; disk space is accounted for. Attacker can prove existence of o=
ne small gpg
<br>&gt;&gt; encrypted file on USB-stick for which user has forgotten passp=
hrase.
<br>
&gt; That just doesn't fly with for e.g. when you computer is sized by the=
=20
police when you are away from home.
<br>
<br>Obviously the police are not going to find one's USB stick on the compu=
ter, when one is not home. The stick is ONLY used for booting and then care=
fully hidden. It does not matter if the &quot;self destruct&quot; works or =
not, what matters is that there is absolutely no reason to even suspect tha=
t a different kind of encryption is being used on the system. It boots from=
 the HDD and uses all the available space, and the police will get the key =
that will unlock the fake system, and that's it. As long as the USB stick i=
s kept safe (which should be trivial to do), they have absolutely nothing t=
o even suggest there being a parallel system encrypted with other keys. And=
 as Jari pointed out, even if they actually get the USB stick too, they rea=
lly cannot prove anything.
<br><br>P.S. they may, however, be smart enough to type one's name on Googl=
e and find out that one has been discussing this topic on this public maili=
ng list.<br><br>

------=_Part_14523_9474555.1148143787292--

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To: Michael Garibaldi <michaelgari@gmail.com>
Cc: linux-crypto@nl.linux.org
Subject: Re: How about deniability? (read:http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
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Michael Garibaldi wrote:
>  >> Here user insists that /dev/hda2 is the root partition. That way all 
> hard
>  >> disk space is accounted for. Attacker can prove existence of one 
> small gpg
>  >> encrypted file on USB-stick for which user has forgotten passphrase.
>  > That just doesn't fly with for e.g. when you computer is sized by the 
> police when you are away from home.
> 
> Obviously the police are not going to find one's USB stick on the 
> computer, when one is not home. The stick is ONLY used for booting and 
> then carefully hidden. It does not matter if the "self destruct" works 
> or not, what matters is that there is absolutely no reason to even 
> suspect that a different kind of encryption is being used on the system. 
> It boots from the HDD and uses all the available space, and the police 
> will get the key that will unlock the fake system, and that's it. As 
> long as the USB stick is kept safe (which should be trivial to do), they 
> have absolutely nothing to even suggest there being a parallel system 
> encrypted with other keys. And as Jari pointed out, even if they 
> actually get the USB stick too, they really cannot prove anything.

When you don't "boot" the system, but inspect the HDD-Image from another 
system
there are a few "obvious" information missing which you had when you 
actually booted the system.

So for the police you would have an unencrypted "boot" partition and 3 
partitions with random data.

 From the unencrypted partition would would get an indication that the 2 
second partition contains a root-filesystem, but that's about what you 
can get from the sample-setup without breaking the decryption.

So from the police-Standpoint there are 3 "unaccounted" partitions.

If you encrypted the whole HDD (including sector 0) the deniability 
would be slightly better as there is no "partition" at all you could say 
that you just hadn't hat time to install the computer. :-)

Or use a random reagion on the HDD and filling the rest with random data.
e.g. when you have a 200GB HDD, fill it with 200GB of random data and 
then just use the range from e.g. 96GB-145GB.
As it shouldn't be possible distinguish the encrypted data from the 
actual random-data you would have enough room for another "container" as 
a decoy.

> P.S. they may, however, be smart enough to type one's name on Google and 
> find out that one has been discussing this topic on this public mailing 
> list.

That's the drawback when you have a (AFAICS) "unique" name.

P.S.
If i'm not mistaken you aren't using your real name.




Bis denn

-- 
Real Programmers consider "what you see is what you get" to be just as
bad a concept in Text Editors as it is in women. No, the Real Programmer
wants a "you asked for it, you got it" text editor -- complicated,
cryptic, powerful, unforgiving, dangerous.


-
Linux-crypto:  cryptography in and on the Linux system
Archive:       http://mail.nl.linux.org/linux-crypto/



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From: Thomas Weinbrenner <thomas@thomas-weinbrenner.de>
To: linux-crypto@nl.linux.org
Subject: Re: How about deniability? (read:http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
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Michael Garibaldi wrote:
> Obviously the police are not going to find one's USB stick on the
> computer, when one is not home. The stick is ONLY used for booting and
> then carefully hidden. It does not matter if the "self destruct" works
> or not, what matters is that there is absolutely no reason to even
> suspect that a different kind of encryption is being used on the
> system. It boots from the HDD and uses all the available space, and
> the police will get the key that will unlock
> the fake system, and that's it. As long as the USB stick is kept safe
> (which should be trivial to do), they have absolutely nothing to even
> suggest there being a parallel system encrypted with other keys. 

The timestamps will show that the files weren't accessed for months or
even years. And there are also all those logfiles in /var/log which
include dates. I think there will be enough proof that the system wasn't
can't be the system you are normally using.

-- 
Thomas Weinbrenner

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From: Jari Ruusu <jariruusu@users.sourceforge.net>
To: Thomas Weinbrenner <thomas@thomas-weinbrenner.de>
Cc: linux-crypto@nl.linux.org
Subject: Re: How about deniability? 
 (read:http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
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Thomas Weinbrenner wrote:
> The timestamps will show that the files weren't accessed for months or
> even years. And there are also all those logfiles in /var/log which
> include dates. I think there will be enough proof that the system wasn't
> can't be the system you are normally using.

Q:  Why haven't files been accessed for months?
A:  Because file system superblocks contain "noatime" default mount option.

Q:  Why aren't there any log files in /var/log/* ?
A:  Because init scripts have been modified to shred and remove /var/log/*
    and some other files and directories in /var on shutdown.

In addition, a shell script, run as cron job once a week from 'normal' root
partition /dev/hda4, does these: (1) Fsck and mount /dev/hda2 (via encrypted
loop) and /dev/hda1 partitions so that their previous fsck and mount times
are updated on their superblocks. (2) Touch some decoy files and directories
from /dev/hda2 partition.

-- 
Jari Ruusu  1024R/3A220F51 5B 4B F9 BB D3 3F 52 E9  DB 1D EB E3 24 0E A9 DD

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From: Matthias Schniedermeyer <ms@citd.de>
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To: Jari Ruusu <jariruusu@users.sourceforge.net>
Cc: Thomas Weinbrenner <thomas@thomas-weinbrenner.de>,
	linux-crypto@nl.linux.org
Subject: Re: How about deniability?  (read:http://www.zdnet.co.uk/print/?TYPE=story&AT=39269746-39020330t-10000025c)
References: <b224d3290605200949g5e135efai7bb97763d227136d@mail.gmail.com> <20060520185431.GA6154@genius.thomas-weinbrenner.de> <44705BB9.B1EA4A97@users.sourceforge.net>
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Jari Ruusu wrote:
> Thomas Weinbrenner wrote:
> 
>>The timestamps will show that the files weren't accessed for months or
>>even years. And there are also all those logfiles in /var/log which
>>include dates. I think there will be enough proof that the system wasn't
>>can't be the system you are normally using.
> 
> 
> Q:  Why haven't files been accessed for months?
> A:  Because file system superblocks contain "noatime" default mount option.
> 
> Q:  Why aren't there any log files in /var/log/* ?
> A:  Because init scripts have been modified to shred and remove /var/log/*
>     and some other files and directories in /var on shutdown.
> 
> In addition, a shell script, run as cron job once a week from 'normal' root
> partition /dev/hda4, does these: (1) Fsck and mount /dev/hda2 (via encrypted
> loop) and /dev/hda1 partitions so that their previous fsck and mount times
> are updated on their superblocks. (2) Touch some decoy files and directories
> from /dev/hda2 partition.

That wouldn't work in the police-case, when the computer was switched on 
when sized, or when you can recover the "real" time of last use.
For perfect denyability you would have to update the "decoy" system 
continously, when the real-system is used.

Or you could configure  syslog to "/dev/null" everything, or switch off 
syslog entirely.
OTOH it would be "fishy" if only of the system-parts were missing that 
provide time-information, even if they are per definition unusable as PROVE.

Otherwise you could still somewhat prove that the "decoy" system wasn't 
the one running when the computer was switched off (as you have the 
switch-off "timestamp").

But if one doesn't need 100% deniability: In an article about 
warez-servers i read that at least once they encountered a server that 
was 100% "on the fly" configured.
The whole system was on ramdisk(/ramfs/tmpfs). After switching of there 
was nothing left, except a bootstrap barebone-system on HDD(*).

A loop-aes-partition with random-key would be equally secure, when 
switched off if configured "on-the-fly" the key would be unrecoverable.
Only the work and time needed to get the system flying the first time 
and every time it is rebooted, for whaterver reason, seams a bit much. ;-)



*: The "root"-servers i worked with allow to be booted via network into 
a "rescure"-system.
This way even the HDD isn't needed to bootstrap the server.

Bis denn

-- 
Real Programmers consider "what you see is what you get" to be just as
bad a concept in Text Editors as it is in women. No, the Real Programmer
wants a "you asked for it, you got it" text editor -- complicated,
cryptic, powerful, unforgiving, dangerous.


-
Linux-crypto:  cryptography in and on the Linux system
Archive:       http://mail.nl.linux.org/linux-crypto/



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