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Re: likely, unlikely and builtin_expect()





I understand the meaning of likely() and unlikely() in linux/compiler.h,
but I don't undertand the meaning of !! in the definition.

#define likely(x)       __builtin_expect(!!(x), 1)
#define unlikely(x)     __builtin_expect(!!(x), 0)

why not this?:

#define likely(x)       __builtin_expect((x), 1)
#define unlikely(x)     __builtin_expect((x), 0)


!!(x) ensures, the first argument to __builtin_expect is always 0 or 1 regardless of input.

Regards,
Mohan



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