Re: timer interrupt

[Christophe Lucas <c.lucas@ifrance.com>]

Please correct me, if I make a mistake.
But, why don't you use/register a kernel timer to make what you want ?

Raghu R. Arur (rra2002@cs.columbia.edu) wrote:
> 
>  instead of changing the timer interrupt why dont u use timer_bh or 
> immediate_bh bottom halves of timer interrupt. i mean u can register ur 
> code to be executed every timer interrupt if u register to these bottom 
> halves.
> 
>  hth,
> raghu
> 
> 
> On Thu, 2 Jan 2003, Geert Fannes wrote:
> 
> > hello,
> > 
> > i am working on a drivermodule to control a stepper motor using the 
> > parallel port. i need a timer mechanism with a higher frequency than the 
> > jiffies clock. i tried to register an interrupt handler for IRQ0, but 
> > the code
> > 
> > request_irq(0,stepper_isr,SA_SHIRQ,"stepper",&iNothing)
> > 
> > fails and returns -16 (16 == EBUSY, 12 == ENOMEM, 22 == EINVAL, so i 
> > guess that the "-" characters in `man request_irq` in the return value 
> > section are really minus signs, and not some item indicators. i mean: 
> > can i interpret "-16" as being EBUSY?). i tried also using the flags 
> > SA_INTERRUPT|SA_SHIRQ, but it gave the same result, so i gues the timer 
> > interrupt cannot be shared using request_irq().
> > 
> > - can anyone tell me what i am doing wrong?
> > - or how i can get my interrupt service routine called at each IRQ0 (i 
> > played a bit with writing interrupt handler in dos using assembler, but 
> > i don't know if i can do the same things in protected mode. if i 
> > remember correct, the isr for irq0 can be found at addres 0x0000 till 
> > 0x0003, so can i just replace this with my isr and call the original 
> > linux timer isr at the end of my isr)?
> > - (or where i can find the linux timer interrupt handler in the source 
> > so i can extend this (last option))?
> > 
> > (i run the latest mandrake and/or the latest debian)
> > 
> > greetings and happy newyear,
> > geert.
-- 
Regards/Cordialement
Christophe
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